SOLUTION: a used car salesman in a small town states that on average, it takes 5 days to sell a car. assume that the probability distribution of the length of the time between sales is expon

Question 860366: a used car salesman in a small town states that on average, it takes 5 days to sell a car. assume that the probability distribution of the length of the time between sales is exponentially distributed
what is the probability that he will have to wait between 6 and 10 days before making another sale?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Poisson distribution

average: 5 days

TI syntax  P(# ≤ x)= poissioncdf(mean, largest x-value).

P(6 ≤ x ≤ 10) = poissioncdf(5, 10) - poissioncdf(5, 6) = .9863  -.7622

0r if You mean

P(6 < x < 10) = poissioncdf(5, 9) - poissioncdf(5, 7) 

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