SOLUTION: The probability that a certain kind of flower seed will germinate is 0.90. a.) If 183 seeds are planted, what is the probability that fewer than 155 will germinate? b.) Wha

Question 857724: The probability that a certain kind of flower seed will germinate is 0.90.

a.) If 183 seeds are planted, what is the probability that fewer than 155 will germinate?
b.) What is the probability that at least 155 will germinate?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

p = .90, n = 183

TI syntax is binomcdf(n, p, largest x-value) for binomial ≤ cumulative probability

a) P(x <155) = binomcdf(183, .90, 154)= .0088

b) P(x ≥ 155) = 1 - binomcdf(183, .90, 154)= .9912

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