Hi,
mean 800 miles and standard deviation 90 miles.
Percentage who preform poorly:= -2.222, NORMSDIST(-2.222) = .0131
a) 200*.0131 = 2.62 0r ~3
b)|NORMSINV(.01)| = 2.3263 =, X = 1009.367 = 1009.4
For the normal distribution:
one standard deviation from the mean accounts for about 68.2% of the set
two standard deviations from the mean account for about 95.4%
and three standard deviations from the mean account for about 99.7%.
Important to Understand z -values as they relate to the Standard Normal curve:
Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
Note: z = 0 (x value the mean) 50% of the area under the curve is to the left and %50 to the right