Hi,

P(z < 1.05) = NORMSDIST(1.05)= .8531  

(85.31% of the area under the normal curve is to the left of z = 1.05)

P(0< z ≤ .24)  = NORMSDIST(.24) - .5 = .5948 - .5 = .0948

Normal distribution: 

Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.  

Note: z = 0 (represents the mean) 50% of the area under the curve is to the left and %50 to the right



 

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