SOLUTION: The probability of a randomly selected car crashing during the year is .0423. If a family has three cars, find the probability that at least one of them has a crash during the year

Question 854651: The probability of a randomly selected car crashing during the year is .0423. If a family has three cars, find the probability that at least one of them has a crash during the year? Thank you for the help.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

 p(crash)= .0423, p(no crash) = .9577

3 cars

P(at least one crash) = 1 - P(no crash) = 1 - (.9577)^3 = 1- .8784 = .1216

Using  

P(no crash) = (.9577)^3 

RELATED QUESTIONS

The probability of a randomly selected car crashing during a year in a certain country is  (answered by jorel1380)
The probability of a randomly selected car crashing during a year in a certain country is  (answered by stanbon)
In a certain city, 55% of the families own only one car and 20% own exactly two cars. One  (answered by Fombitz)
a car agency has 18 red cars and 12 blue cars. If 4 of the cars are randomly selected for  (answered by jorel1380,Tatiana_Stebko)
If the probability of being hospitalized during a year is 0.05, find the probability that  (answered by jorel555)
in the past year, 13%of businesses have eleminated jobs. if five businesses are randomly... (answered by ewatrrr)
Can someone please help me understand this.

Based on past records, a car insurance... (answered by stanbon)
A car insurance company has determined that 6% of all drivers were involved in a car... (answered by )
A car insurance company has determined that 9% of all drivers were involved
in a car... (answered by Theo)