SOLUTION: suppose that women's body temperatures are normally distributed with a mean of 98.4 F and a standard devidation of 0.70 F. what is the 95th percentile of womens body temperatures.

Question 854097: suppose that women's body temperatures are normally distributed with a mean of 98.4 F and a standard devidation of 0.70 F. what is the 95th percentile of womens body temperatures.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
suppose that women's body temperatures are normally distributed with a mean of 98.4 F and a standard devidation of 0.70 F. what is the 95th percentile of womens body temperatures
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Find the z-value with a left-tail of 0.95:: invNorm(0.95) = 1.645
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Find the corresponding body temperature
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x = z*s + u
x = 1.645*0.7 + 98.4 = 99.55 degrees
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Cheers,
Stan H.
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