SOLUTION: binomial distribution A quality inspector has drawn a sample of 16 light bulbs from a recent production line. Supposed 20% of the bulbs in the lot are defective. What is the pr

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Question 852119: binomial distribution
A quality inspector has drawn a sample of 16 light bulbs from a recent production line. Supposed 20% of the bulbs in the lot are defective. What is the probability that exactly 6 bulbs from the sample are defective?

Found 2 solutions by ewatrrr, rothauserc:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Using TI: The syntax is binompdf(n, p, x-value).
P(x = 6) = binompdf(16,.20,6)
0r
P (x = 6)=
Answer by rothauserc(4718)   (Show Source): You can put this solution on YOUR website!
We are going to use the General Binomial Probability formula
P(k out of n) = n!/(k!(n-k)!) * p^k * (1-p)^(n-k)
p = .20
k = 6
n = 16
P(6 out of 16) = 16! /(6!(16-6)!) * .2^6 * (1-.2)^(16-6)
P(6 out of 16) = 8008 * 6.4e-5 * 0.1073741824
P(6 out of 16) = 0.0550 = 0.06

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