Hi,
mean of 266 days and a standard deviation of 16
Sample of 20, SD of population = 16/sqrt(20) = 3.5777
= -1.6771
NORMSDIST(-1.6771)= .0476 0r 4.76%
P(-5/3.5777 ≤ z ≤ 5/3.5777) = P(-1.3975 ≤ z ≤ 1.3975)
NORMSDIST(-1.3975) = .0811
P(sample mean is within 5 days of the population mean) =