Hi,

A fair die is rolled twice (36 outcomes)

P(sum between 3 and 7) = P(sum is 4, 5 0r 6) = 3/36 + 4/36 + 5/36 = 12/36 = 1/3

___1_2_3__4__5__6

1|_2_3_4__5__6__7

2|_3_4_5__6__7__8

3|_4_5_6__7__8__9

4|_5_6_7__8__9_10

5|_6_7_8__9_10_11

6|_7_8_9_10_11_12

 

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