SOLUTION: A biologist finds that 24% of fruit flies have short wings and 47% have eye defects. Assuming these two events are independent, what is the probability that a randomly selected

Question 851028:
A biologist finds that 24% of fruit flies have short wings and 47% have eye defects. Assuming these two events are independent, what is the probability that a randomly selected fruit fly has neither short wings nor eye defects?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A biologist finds that 24% of fruit flies have short wings and 47% have eye defects. Assuming these two events are independent, what is the probability that a randomly selected fruit fly has neither short wings nor eye defects?
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P(not short wings) = 1-0.24 = 0.76
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P(not eye defects) = 1-0.47 = 0.53
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P(not short wings AND not eye defects) = 0.74*0.53 = 0.3922
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Cheers,
Stan H.
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