Hi,

p = .05,  n = 100

using TI Calculator

P(x=3) = The syntax is binompdf(n, p, x-value)= binompdf(100, .05,3)

Or

 P = (.05)^3(.95)^100  

Note: The probability of x successes in n trials is: 

P (x)=  (p)^x(q)^(n-x) where p and q are the probabilities of success and failure respectively. 

In this case p = .05 & q  = .95

 =  

 = 

B. What is the probability, rounded to four decimal places that the box will contain at most 7 defective bolts? 

find P(x ≤ 7)= binomcdf(n, p, largest x-value) = binomcdf(100, .05, 7).

 c. what is the probability, rounded to four decimal places that the box will contain less than 4 defective bolts?

find P(x < 4)= binomcdf(n, p, largest x-value) = binomcdf(100, .05, 3). 

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