SOLUTION: if eight different books are arranged at random in a shelf, what is the probability that a certain pair of books
a. will be beside each other?
b. will not be together?
Hi, Previously Posted
eight different books 8! total ways of arranging on shelf
thinking OF A 'PAIR' AS ONE UNIT
P(beside each other) = 7!/8!
P(not be together) = 1 - P(together) = 1- 7!/8!