Hi,
p(note right= .99, n = 60
P(x=60) = binompdf(60, .99, 60).
P(x=59) = binompdf(60, .99, 59).
P(x=58) = binompdf(60, .99, 58)
P(at least two mistakes) = 1 - binomcdf(60, .01, 1).
P(> 2 mistakes) = binompdf(60, .01, 2).
b. what must be Clara's probability of getting any one note right
if she wants to have a 95% probability of getting all 60 notes right?
x^60 = .99
x == .9998 0r 99.98 % probability of correct