Hi,

Note: The probability of x successes in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. 

In this case p = .30 and q = .70   and n = 5 

 

Using the 'formula' is the 0r

Using TI Calculator

a. binompdf(5,.30, 0) = .1681  0r P = (.30)^0(.70)^5

 binompdf(5,.30, 1) = .3602    0r P = 5(.30)^1(.70)^4

binompdf(5,.30, 2) =  .3087    0r P = 10(.30)^2(.70)^3

binompdf(5,.30,3) =   .1323   0r  P = 10(.30)^3(.70)^2

binompdf(5,.30, 4) =  .0284   0r P = 5(.30)^4(.70)^1

binompdf(5,.30, 5) =  .0024   0r P = (.30)^5(.70)^0

c. P(x≥ 2) = 1 - P(x=0)- P(x=1) =   1 - .1681 - .3602

0r  Using TI

1 – binomcdf(n, p, largest x-value) = 1 - binomcdf(5,.30, 1) 

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