SOLUTION: Given a standard normal distribution, determine the area between z=-2.35 and z=-2.33 and enter as a decimal rounded to the nearest thousandths place.

Question 847358: Given a standard normal distribution, determine the area between z=-2.35 and z=-2.33 and enter as a decimal rounded to the nearest thousandths place.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Using the TI Calculator

The syntax is normalcdf(smaller z, larger z).

P(-2.35 ≤ z ≤ -2.33). = normalcdf(-2.35, -2.33).

Or

 P(-2.35 ≤ z ≤ -2.33) =  P(-z ≤ -2.33) - P(2.35 ≤ )

                                  = .0099 - .0094 = = .001 (rounded the decimal to the nearest thousandths place per directions) 

RELATED QUESTIONS

Given a standard normal distribution, determine the area between z=-2.35 and z=-2.33 and... (answered by ewatrrr)
A distribution of values is normal with a mean of 58.2 and a standard deviation of 40.3.
 (answered by Theo)
Use the standard normal distribution to calculate P(z< 2.46) and enter as a decimal... (answered by ewatrrr)
Use the standard normal distribution to calculate P(z< 2.46) and enter as a decimal... (answered by ewatrrr)
  	
A normal distribution has mean μ = 14.6 and standard deviation σ = 3.02.... (answered by Edwin McCravy)
What percent of the total population is found between the mean and the z-score given?... (answered by Theo)
What percent of the total population is found between the mean and the z-score given? z =  (answered by Boreal)
Standard Normal Distribution Curve

1. Find the area under the standard normal... (answered by stanbon)
A distribution of values is normal with a mean of 170 and a standard deviation of 2.... (answered by Boreal)