SOLUTION: Two dice are thrown once. Find the probability of getting a multiple of 3 on the first die or a total of 8

Question 847210: Two dice are thrown once. Find the probability of getting a multiple of 3 on the first die or a total of 8
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
I apologize for last time. I made a slight error.
P[multiple of 3] = 1/3 = 12/36
P[sum of 8] = 5/36
However as I said last time (3,5) is not the only roll that satisfies both, we also have (6,2). This means we need to take in account the 2 cases out of 36 where both events take place.
So we calculate 12/36 + 5/36 - 2/36 = 5/12 which is our answer.
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