Hi,

using a TI Calculator

The syntax is normalcdf(smaller, larger, µ, σ)

mean age normalcdf(73, 9999, 75,6)= .6305   0r 63.05%

Note: The 9999 is used as the larger value to be at least 5 standard deviations from the mean.



Or  z = 

  P(z≤ -1/3) =  .3695   and 1 - .3695 = .6305 

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