Hi

Note: The probability of x successes in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. 

In this case p(defective) = .1 & q = .9 

nCx = 

P(of six items two are defective)= 6C2(.10)^2(.90)^4 = .0984

P(of ten items, at least one is defective) = 1 - P(none defective)

 1-(.90)^6 = 1-.5314= .4686 

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