# SOLUTION: In a package of candy coated chocolates, 30 percent of the candies are brown, 20% of them are yellow, and 20% of them are red, there are 10% each of orange, green,and blue. if Rona

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: In a package of candy coated chocolates, 30 percent of the candies are brown, 20% of them are yellow, and 20% of them are red, there are 10% each of orange, green,and blue. if Rona      Log On

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 Question 83651: In a package of candy coated chocolates, 30 percent of the candies are brown, 20% of them are yellow, and 20% of them are red, there are 10% each of orange, green,and blue. if Ronan reaches into a package and pulls out 12 candies, what is the probability that A) Exactly 2 of them would be red B) at most 2 of them would be red C) none of them would be blue Round your answers to the nearest tenth of a percent.Answer by stanbon(57290)   (Show Source): You can put this solution on YOUR website!In a package of candy coated chocolates, 30 percent of the candies are brown, 20% of them are yellow, and 20% of them are red, there are 10% each of orange, green,and blue. if Ronan reaches into a package and pulls out 12 candies, what is the probability that A) Exactly 2 of them would be red P(2red of 12) = 12C2(0.20)^2(0.80)^10 = 0.2835 ------------ B) at most 2 of them would be red Using a Ti calculator you get: P(0,1,or 2 are red) = binomcdf(12,0.2,2) = 0.5583 --------------- C) none of them would be blue P(12 not blue) = 0.9^12 = 0.2824 --------------------- Cheers, Stan H.