rounding to 4 decimal digits, the probability that a member of the office will be a female is .4557 and the probability that the member of the office will be a male is .5443.
it appears you are looking for a binomial distribution.
assuming that is what you are looking for, the distribution would look like this.
n x p(x) p(1-x) ncx probability of x occurrences
8 0 0.5443 0.4557 1 0.001859654
8 1 0.5443 0.4557 8 0.017769758
8 2 0.5443 0.4557 28 0.074286325
8 3 0.5443 0.4557 56 0.177459058
8 4 0.5443 0.4557 70 0.264952177
8 5 0.5443 0.4557 56 0.253172648
8 6 0.5443 0.4557 28 0.151198017
8 7 0.5443 0.4557 8 0.051598533
8 8 0.5443 0.4557 1 0.00770383
total probability >>>>> 1
n is the total number of people in the office.
x is the number of males.
p(x) is the probability that it will be a male.
p(1-x) is the probability that it will be a female.
nCx is the number of possible combinations you can get from 8 people taken x at a time..
probability of x occurrences is given by the formula:
p(x number of males is equal to: nCx * p(x)^x * p(1-x)^(n-x)
for example:
the probability there will be 5 males in the office is equal to:
8C5 * (.5443)^5 * (.4557)^3 which is equal to:
56 * (.5443)^5 * (.4557)^3 which is equal to .25317
this means there is a 25% probability that the office will contain 5 males.
i'm pretty sure this is what you want.
let me know if it's something different.
the total probability should always equal 1 which is what is shown in the table.
this is a good check to see that you did it correctly.