SOLUTION: Could anyone help me with this problem?
Suppose that women's heights are normally distributed w/ mean=63.6 inches & standard deviation=2.5 inches. Find the probability that
(a)
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Question 833262: Could anyone help me with this problem?
Suppose that women's heights are normally distributed w/ mean=63.6 inches & standard deviation=2.5 inches. Find the probability that
(a) if 1 woman is randomly selected that her height is less than 60 inches.
(b) if 36 are randomly selected, that they have a mean height less than 60 inches
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose that women's heights are normally distributed w/ mean=63.6 inches & standard deviation=2.5 inches. Find the probability that
(a) if 1 woman is randomly selected that her height is less than 60 inches.
z(60) = (60-63.6)/2.5 = -3.6/2.5 = -1.44
P(x < 60) = P(z < -1.44) = normalcdf(-100,-1.44) = 0.0749
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(b) if 36 are randomly selected, that they have a mean height less than 60 inches
z(60) = (60-63.6)/[2.5/sqrt(36) = 6*-1.44 = -8.64
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P(x-bar < 60) = P(z < -8.64) = normalcdf(-100,-8.64) = 0 to 4 decimals.
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Cheers,
Stan H.
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