SOLUTION: hello, could someone help me please, I have this questions.. 1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0 a)how many values are lar

Question 824224: hello,
could someone help me please, I have this questions..
1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0
a)how many values are larger than 27.00
(report answer to nearest integer)
b) how many values are btween 23.00 and 28.00
(report answer to nearest integer)

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0
a)how many values are larger than 27.00
z(27) = (27-24)/4 = 3/4
P(x > 27) = P(z > 3/4) = 0.2266
----
Answer: 0.2266*900 = 204
----------------------------------------
b) how many values are btween 23.00 and 28.00
z(28) = (28-24) = 4/4 = 1
P(27 < x < 28) = P(3/4 < z < 1) = normalcdf(3/4 , 1) = 0.06
------
Ans: 0.06*900 = 54
===================
Cheers,
Stan H.
===================

RELATED QUESTIONS
consider a set of 900 of data values with a mean of 24 and a standard deviation of... (answered by stanbon)

Can someone please help me here? I am so confused, I am seeing so many different... (answered by stanbon)

Hello Could I please get some help with this problem. I am really confused on how to... (answered by Theo,solver91311)

Hello, Could someone please tell me if I have the following data correct from a... (answered by stanbon)

I am in need of some help, this is my first statistics class and we are in the second... (answered by stanbon)

Can someone please help me with this? For the following set of data: 13, 10, 11, 8, 14, (answered by ewatrrr)

A set of 50 data values has a mean of 34 and a variance of 25. I. Find the standard... (answered by CubeyThePenguin)

Please Help Consider a normal population with � = 25 and σ = 7.0. (A) Calculate (answered by jim_thompson5910)

hi. Could you help me understand standard deviation? Here is my problem: Consider... (answered by venugopalramana)