There are 9 arithmetic means between 11 and 51. The sum of the progression is 11, _, _, _, _, _, _, _, _, _, 51 Notice with 9 terms between them, that gives a sequence of 11 terms, counting the 9 and the 51, so n=11, a1=11, a11 = 51. (There are two elevens, so don't get them mixed up :). If we use this sum formula, we don't need d: Sn =(a1 + an) S11 = (11 + 51) S11 = (62) S11 = 341 Edwin