SOLUTION: 8% of the employees are left handed. If 20 employees are randomly selected, what is the probability that none of them are left handed? what is the probability that at most 2 are le

Question 816586: 8% of the employees are left handed. If 20 employees are randomly selected, what is the probability that none of them are left handed? what is the probability that at most 2 are left-handed? what is the standard deviation and mean for the number of left handed employees?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
8% of the employees are left handed.
If 20 employees are randomly selected, what is the probability that none of them are left handed?
Ans: 0.92^20 = 0.1887
---------------------------
what is the probability that at most 2 are left-handed?
P(0<= x <=2) = binomcdf(20,0.08,2) = 0.7879
----------------------
what is the standard deviation and mean for the number of left handed employees?
-------
mean = np = 20*0.08 = 1.6
std = sqrt(npq) = sqrt(1.6*0.2) = 0.5657
==================
Cheers,
Stan H.

RELATED QUESTIONS
(a) It is noted that 8% of ART students are left handed. if 20 students are randomly... (answered by solver91311)

Its is noted that 8% of school student are left handed. IF 20 students are randomly... (answered by ewatrrr)

its is noted that 8% of school students are left handed. If 20 students are randomly... (answered by ewatrrr)

a) It is noted that 8% of students are left handed. If 20 students are randomly selected, (answered by ewatrrr)

8% of student are left handed. if 20 student are randomly selected calculate... (answered by ewatrrr)

8% of students are left handed. If 50 (FIFTY) classes of 20 (TWENTY) students are... (answered by mathmate)

On a very hot summer day, 5% of the production employees at Midland States Steel are... (answered by edjones)

If 50 (FIFTY) classes of 20 (TWENTY) students are randomly selected, what is the... (answered by Alan3354)

Question 972677: If 50 (FIFTY) classes of 20 (TWENTY) students are randomly selected,... (answered by Edwin McCravy)