Hi,

Re Reply: note highlighted

Note: The probability of x successes in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. 

In this case p = 1/6. q = 5/6 and n = 4  nCx = 



A die is thrown four times. Determine the probability of throwing the following.

 (a) zero 3's (Round your answer to four decimal places.)  = .4823

  P(x=0) = 4C0 = (5/6)^4

 (b) one 3 (Round your answer to four decimal places.) = .3858

  P(x = 1) = 4C1((1/6)^1(5/6)^3  

 (c) two 3's (Round your answer to four decimal places.) = .1157

 P(x = 2) = 4C2((1/6)^2(5/6)^2 

 (d) three 3's (Round your answer to four decimal places.) = .0154

 P(x = 3) = 4C3((1/6)^3(5/6)^1

 (e) four 3's (Round your answer to five decimal places.)= .00077

 P(x = 4) = 4C4((1/6)^4(5/6)^0

Note: The probability of x successes in n trials is: 

P = nCx*  where p and q are the probabilities of success and failure respectively. In this case p = 1/6. q = 5/6 and n = 4  nCx = 

 

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