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put this solution on YOUR website!Among 100 people randomly chosen in a survey, 10 stated that they believed that the elected representatives are honest most of the time. The approximate 95% confidence interval for the percentage of the population who believe that such people are honest most of the time is
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p-hat = 10/100=0.1
E=z*sqrt(pq/n)
E=1.96sqrt(0.1*0.9/100)
E=1.96*0.0009
E=0.0018
CI: (p-hat-E,p-hat+E)
CI: (0.1-0.0018, 0.1+0.0018)
CI: (0.0982,0.1018)
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Cheers,
Stan H.