SOLUTION: I have figured out how to find the probability when given P, but the q is now confusing me. I have tried a few different ways and I have three formulas in front of me. Very confuse

Question 803276: I have figured out how to find the probability when given P, but the q is now confusing me. I have tried a few different ways and I have three formulas in front of me. Very confused-please help! I am also able to see that the answer is " 0.0818" with no clue how they got to that point.
Assume that a procedure yields a binomial distribution with a trial repeated n=13 times. Find the probability of x=5 successes given the probability q=0.42 of failure on a single trial.
P(X=5)

Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
Use the binomial probability formula,
(1) P(x=5) = (n!/(n-x)!/x!)*(p^x)*(q^(n-x))
where
q = 0.42
p = 1 - q = 0.58
n = 13
x = 5
Place the varible values into (1) and get
(2) P(x=5) = (13!/8!/5!)*(0.58^5)*(0.42^8) or
(3) P(x=5) = 1287*(0.58^5)*(0.42^8) or
(40 P(x=5) = 0.0818
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