SOLUTION: In a bag, there are 8 blue balls and 6 red. 2 balls are picked up without replacement. So what is the probability of picking red ball in 2nd attempt knowing that a blue ball has a

Question 800560: In a bag, there are 8 blue balls and 6 red. 2 balls are picked up without replacement. So what is the probability of picking red ball in 2nd attempt knowing that a blue ball has already been extracted?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a bag, there are 8 blue balls and 6 red. 2 balls are picked up without replacement. So what is the probability of picking red ball in 2nd attempt knowing that a blue ball has already been extracted?
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P(red | blue) = P(red and blue)/P(red) = [(8/14)(6/13)]/[6/14] = 0.6154
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Cheers,
Stan H.
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