SOLUTION: <pre>Suppose S and T are mutally exclusive. P(S)=6% P(T)= 29% (1) Find P(S and T) (2) Find P(S or T)</pre>

Question 79980:
Suppose S and T are mutally exclusive. P(S)=6% P(T)= 29% (1) Find P(S and T) (2) Find P(S or T)

Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!

suppose S and T are mutally exclusive. 

P(S)=6%  P(T)= 29%

(1)  Find P(S and T)

Since they are mutually exclusive, they cannot both
occur at the same time.  

So P(S and T) is the probability of an impossible
event, so P(S and T) = 0

---------------------------------------------------

(2)  Find P(S or T)

P(S or T) = P(S) + P(T) - P(S and T)

P(S or T) = .06 + .29 - 0 

P(S or T) = .35 = 35%

Edwin

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