SOLUTION: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face v

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Question 797686: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event : The sum is greater than 7 .
Event : The sum is divisible by 4 or 6 (or both).

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Sum Ways # of Ways
21,11
31,2; 2,12
41,3; 2,2; 3,13
51,4; 2,3; 3,2; 4,14
61,5; 2,4; 3,3; 4,2; 5,15
71,6; 2,5; 3,4; 4,3; 5,2; 6,16
82,6; 3,5; 4,4; 5,3; 6,25
93,6; 4,5; 5,4; 6,34
104,6; 5,5; 6,43
115,6; 6,52
126,61


The probability of anything is the number of ways that it can happen that you would consider a success divided by the number of ways it can happen total -- successes and failures.

If you add up the number of total ways that you can roll a pair of dice you get 36. So, for a 6-sided die rolled twice or two 6-sided dice rolled once, the denominator of the probability fraction is always 36. The numerator is just the sum of the ways that whatever you want to happen can happen.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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