SOLUTION: A Travel Weekly International Air Transport Association survey asked business travelers about the
purpose for their most recent business trip. 19% responded that it was for an in
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Question 788781: A Travel Weekly International Air Transport Association survey asked business travelers about the
purpose for their most recent business trip. 19% responded that it was for an internal company visit.
Suppose 950 business travelers are randomly selected.
a. What is the probability that more than 25% of the business travelers say that the reason for their
most recent business trip was an internal company visit?
b. What is the probability that between 15% and 20% of the business travelers say that the reason for
their most recent business trip was an internal company visit?
c. What is the probability that between 133 and 171 of the business travelers say that the reason for
their most recent business trip was an internal company visit?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent business trip. 19% responded that it was for an internal company visit.
p = 0.19
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Suppose 950 business travelers are randomly selected.
a. What is the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit?
z(0.25) = (0.25-0.19)/sqrt[0.19*0.81/950] = 1.4907
P(p > 0.25) = P(z > 1.4907) = 0.0680
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b. What is the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit?
Find the z-values of 20% and 15%; then find the probability between them.
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c. What is the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit?
Find 133/950 and 171/950
Find their z-values.
Find the probability between them.
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Cheers,
Stan H.
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