SOLUTION: Based on the equation, Z = (x - m)/sd and frequency distribution, please explain the answer to the following:
Bob takes an online IQ test and finds that his IQ according to the
Algebra.Com
Question 787538: Based on the equation, Z = (x - m)/sd and frequency distribution, please explain the answer to the following:
Bob takes an online IQ test and finds that his IQ according to the test is 134. Assuming that the mean IQ is 100, the standard deviation is 15, and the distribution of IQ scores is normal, what proportion of the population would score higher than Bob? Lower than Bob?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Based on the equation, Z = (x - m)/sd and frequency distribution, please explain the answer to the following:
Bob takes an online IQ test and finds that his IQ according to the test is 134. Assuming that the mean IQ is 100, the standard deviation is 15, and the distribution of IQ scores is normal, what proportion of the population would score higher than Bob? Lower than Bob?
------
z(134) = (134-100)/15
----
z(134) = 34/15 = 2.2667
---------
Proportion higher = P(z > 2.2667) = normalcdf(2.2667,100) = 1.17%
---------
Proportion lower = 100% - 1.17% = 98.83%
===================
Cheers,
Stan H.
===================
RELATED QUESTIONS
How do I solve the following problem based on the formula, Z = (x-m)/sd
The graduate... (answered by stanbon)
Bob takes an online IQ test and finds that his IQ according to the test is 134. Assuming... (answered by stanbon)
suppose that the frequency distibution of scores on an examination is closely described... (answered by ewatrrr)
1. The graduate selection committee wants to select the top 10% of applicants. On a... (answered by stanbon)
Describe the normal distribution in terms of z-score and the probability of an outcome... (answered by Boreal)
A normal distribution that has a mean of 100 and sd of 8. I have determined the z scores... (answered by stanbon)
AAA reports that the average time it takes to respond to an emergency call is about 25... (answered by stanbon)
7. Answer the following questions based on the frequency distribution table you got in... (answered by greenestamps)
My final passing grade is depending on some of these problems. (I have tried working out... (answered by ewatrrr)