SOLUTION: The probability that an individual is left-handed is .20. Let the random variable X bethe number of left-handers in a class of 20 students. Assuming the random variable X has a bin

Question 767788: The probability that an individual is left-handed is .20. Let the random variable X bethe number of left-handers in a class of 20 students. Assuming the random variable X has a binomial distribution:
a) What is the probability distribution, P(X) of the random variable X.
b) What is the mean number (expected value) of left-handers in the class?
c) What is the probability that there is exactly 5 left-handers in the class?
d) What is the probability that the number of left-handers are between 6 and 10 inclusively (including 6 and 10)?
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
The probability that an individual is left-handed is .20. Let the random variable X bethe number of left-handers in a class of 20 students. Assuming the random variable X has a binomial distribution:
a) What is the probability distribution, P(X) of the random variable X.
for x = 0,1,2,...,20
b) What is the mean number (expected value) of left-handers in the class?
Mean, E(X) = np = 20(0.2) =
c) What is the probability that there is exactly 5 left-handers in the class?
=
d) What is the probability that the number of left-handers are between 6 and 10 inclusively (including 6 and 10)?
P(6 ≤ X ≤ 10) = =
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