SOLUTION: Ms. Rosse is a Head Nurse at TCH. Her patient wanted an update of her progress. The temperatures are normally distributed with mean 101.1F and the standard deviation is 1.8F. She r
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Question 764805: Ms. Rosse is a Head Nurse at TCH. Her patient wanted an update of her progress. The temperatures are normally distributed with mean 101.1F and the standard deviation is 1.8F. She reads a report that says that in 16 readings the patient’s mean temp was 102.2F. Find the probability that the mean patient’s temperature was at most 102.2F.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Ms. Rosse is a Head Nurse at TCH. Her patient wanted an update of her progress. The temperatures are normally distributed with mean 101.1F and the standard deviation is 1.8F. She reads a report that says that in 16 readings the patient’s mean temp was 102.2F. Find the probability that the mean patient’s temperature was at most 102.2F.
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t(102.2) = (102.2-101.1)/[1.8/sqrt(16)] = 2.4444
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P(temp > 102.2) = P(t > 2.4444 when df=15) = 0.0137
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Cheers
Stan H.
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