SOLUTION: FINDING SAMPLE SIZE.
Q1. margin of error:$125, confidence level:95%,standard deviation=$500
Algebra.Com
Question 75557: FINDING SAMPLE SIZE.
Q1. margin of error:$125, confidence level:95%,standard deviation=$500
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
FINDING SAMPLE SIZE.
Q1. margin of error:$125, confidence level:95%,standard deviation=$500
-----------
E=z*(sigma/sqrt(n))
sqrt(n) = z*(sigma)/E
sqrt(n) = 1.96(500)/125
sqrt(n) = 7.84
n=61 (rounded to whole number)
========
Cheers,
Stan H.
RELATED QUESTIONS
Find the sample size.
Margin of error = $125, confidence level = 95%, standard deviation (answered by Boreal)
Find the margin of error (E) of a confidence estimate interval, when the confidence level (answered by Boreal)
Determine the necessary sample size for a confidence interval around a sample mean: Set... (answered by Boreal)
I am stuck on how to solve this. Use the given margin of error, confidence level, and... (answered by Theo)
A population mean is to be estimated from the sample described. Round your answer to one... (answered by Boreal)
Keep Confidence Level 90%. For Sample size 4, Sample Mean 26 and sample standard... (answered by stanbon)
Assuming a standard deviation of 6 hours, what is the required sample size if the error... (answered by stanbon)
Find the margin of error E that corresponds to the given statistics and confidence level:
(answered by Boreal)
Use the given data to find the minimum sample size required to estimate the population... (answered by Boreal)