SOLUTION: Show that one out of n,n+3,n+6,n+9 is divisible by n when n is a natural number?
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Question 755327: Show that one out of n,n+3,n+6,n+9 is divisible by n when n is a natural number?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
In order to make the divisible by 
claim in general, you must define the Natural numbers as the positive integers. Your premise is generally false given that it is possible for the set of Natural numbers to have 0 as an element. See Wikipedia: In mathematics, a natural number is either a positive integer (1, 2, 3, 4, …) or a non-negative integer (0, 1, 2, 3, 4, …). The former definition is generally used in number theory, while the latter is preferred in set theory and computer science.
However, you can say: 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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