SOLUTION: A committee of 5 people is selected at random from a group of 16 men and 12 women. Find the probability that the committee contains at least 2 women. Tried it, is this the right f

Question 746759: A committee of 5 people is selected at random from a group of 16 men and 12 women. Find the probability that the committee contains at least 2 women. Tried it, is this the right formula to use -----

1-(16C3*12C2/28C5) if not can you show me
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A committee of 5 people is selected at random from a group of 16 men and 12 women. Find the probability that the committee contains at least 2 women. ==================================================
P(at least 2 women) = 1 - [P(no women) + P(1 women)]
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= 1 - [16C5/28C5 + (12C1*16C4)/28C12)]
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= 1 - [0.2667]
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= 0.7333
==============
Cheers,
Stan H.
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