SOLUTION: 7. 10.8% of American women have diabetes. Consider a sample of seventy-two ran-domly selected American women. a) What is the probability that exactly five of these women have d

Question 746033: 7. 10.8% of American women have diabetes. Consider a sample of seventy-two ran-domly selected American women.
a) What is the probability that exactly five of these women have diabetes?
b) What is the probability that more than ten of these women have diabetes?
c) What is the probability that between seven and nine, inclusively, of these women have diabetes?
Let N denote the number of women with diabetes in the sample.
d) Determine the largest whole number n such that P{N ≤ n} ≤ 0.05.
e) Determine the smallest whole number n such that P{N ≥ n} ≤ 0.05.
f) Efficiently determine the expected value and standard deviation of N.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
10.8% of American women have diabetes. Consider a sample of seventy-two ran-domly selected American women.
a) What is the probability that exactly five of these women have diabetes?
P(x=5) = 72C5*(0.108)^5(0.892)^67 = 0.097
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b) What is the probability that more than ten of these women have diabetes?
P(10<= x <=72) = 1-P(0<= x <=9) = 1-binomcdf(72,0.108,9) = 0.247
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c) What is the probability that between seven and nine, inclusively, of these women have diabetes?
Find binomcdf(72,0.108,9)-binomcdf(72,0.108,6)
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Let N denote the number of women with diabetes in the sample.
d) Determine the largest whole number n such that P{N ≤ n} ≤ 0.05.
n = 7
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e) Determine the smallest whole number n such that P{N ≥ n} ≤ 0.05.
n = 8
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f) Efficiently determine the expected value and standard deviation of N.
u = np = 72*0.108 = 7.776
std = sqrt[7.776*0.892] = 2.634
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Cheers,
Stan H.
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