1. First reason why the problem is flawed: P(B|A) == = = 2. That's impossible because all probabilities are between 0 and 1. 2. Second reason why the problem is flawed: P(A and B) can never be greater than P(A) or greater than P(B), yet we are given the impossible case P(A and B)=0.40 and P(A)=0.20 Edwin