SOLUTION: Find the prob. of E = {(a, b): a>b} where a, b are scores of two dice ordered D1, D2, a being the score of D1 and b that of D2.

Question 740837: Find the prob. of E = {(a, b): a>b} where a, b are scores of two dice ordered D1, D2, a being the score of D1 and b that of D2.
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

If comes up 1, then there are zero ways that can be strictly less than . If comes up 2, then there is exactly 1 way that can be strictly less than D_2]. implies there are 2 ways, and so on. Total of 15 possibilities for . There are 36 possible combinations of 2 dice.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the prob. of E = {(a, b): a>b} where a, b are scores of two dice ordered D1, D2, a being the score of D1 and b that of D2.
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Sketch a 6 by 6 array of pairs.
Count the pairs where column values are greater than row values.
Divide that count by 36 to get the probabilty of E.
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Cheers,
Stan H.

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