To be successful you either have to get HH or HTHH or HTHTHH or HTHTHTHH or get TT or THTT or THTHTT or THTHTHTT So it's the probability of starting with a head and ending with two heads + the probability of starting with a tail and ending with two tails. The desired probability is the sum of sums of these two infinite geometric series: 1. P(HH)+P(HTHH)+P(HTHTHH)+··· =+··· = +··· 2. P(TT)+P(THTT)+P(THTHTT)+··· = +··· = +··· Each of those has a1= and r = S∞ = = = = = So the desired probability is twice that or Edwin