SOLUTION: n=10
p=0.48
q=0.52
x=8
how to calculate this:
10c8(0.48)^8(0.52)^2
please let me know.
Algebra.Com
Question 730393: n=10
p=0.48
q=0.52
x=8
how to calculate this:
10c8(0.48)^8(0.52)^2
please let me know.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
10 C 8 = (10!)/(8!*(10-8)!)
10 C 8 = (10!)/(8!*2!)
10 C 8 = (10*9*8!)/(8!*2!)
10 C 8 = (10*9)/(2!)
10 C 8 = (10*9)/(2*1)
10 C 8 = 45
-------------------------------------------------------
(10 C 8)(0.48)^8(0.52)^2 = (45)*(0.48)^8(0.52)^2
(10 C 8)(0.48)^8(0.52)^2 = (45)*0.0028179280429*0.2704
(10 C 8)(0.48)^8(0.52)^2 = 0.034288548426
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