SOLUTION: 5. (50 pts). It is known nationwide, that in 50,000 people on average in three days 1 person needs emergency intensive care help. (a) How many people would you expect t

Question 730220: 5. (50 pts). It is known nationwide, that in 50,000 people on average in three days 1 person needs emergency intensive care help.
(a) How many people would you expect to need emergency intensive care help in a city of 150,000 residents during a week?

150,000/50,000=(3 people every 3 days)=(1 person per day)*(7 days)=7 People
Let X be the number if people in the city above, who may need intensive care help during a week. What is the distribution of the r.v. X and what is its standard deviation?
NAME the distribution:
St.dev. =

(b) What is the probability that at least six people will need intensive care on a randomly selected week?

(c) If records of six cities of 50,000 residents each are reviewed in regard to the intensive care visits on a particular week, how likely is it that at least in four of these cities will be no patient visit during this week? (Make an appropriate model.)

(d) In a city of 100,000 residents in a humid hot summer day there were observed 11 visits of the intensive care clinic. Are there sufficient evidences that during this particular day the city experienced high rate of intensive care needs? Test appropriate hypotheses and report the p-value and your conclusion.

P-value =
(e) In the situation of (d) find a 99 % upper confidence bound for the rate of intensive care needs in that day
99 % upper confidence bound =

Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!

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