SOLUTION: A box contains 7 red apples and 4 yellow apples. John takes out one apple at random, notes its color, and places it on a table. Then he takes out a second apple at random, note

Question 729060: A box contains 7 red apples and 4 yellow apples.
John takes out one apple at random, notes its color,
and places it on a table. Then he takes out a second apple
at random, notes it color, and places it on the table. What is the probability that both apples are red?

Answer by erika514(39) (Show Source): You can put this solution on YOUR website!
Hi...this one is simple. Here we go!
So we know that we have 11 apples total. We need to find the probability of getting a red apple, then without replacing or putting that apple back, we need to get another red apple from the box. After our first pick, we will only have 10 apples left. Knowing this information will help us to set up our problem. First we need to find the probability of getting a red apple on our first pick. We have 7 red apples and we have 11 apples total so our probability of getting a red apple is 7/11. For our second pick, we have 10 apples left and we have 6 red apples left since we are not replacing the red apple that was picked. So our probability for picking a red apple now is 6/10. We are going to multiply our two probabilies to find the combined probability. When we multiply 7/11*6/10 which can simplified to 7/11*3/5 we should get 21/55 as our final answer. GOOD LUCK! Let me know if you have any more questions. :)
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