SOLUTION: 7% of the items produced on a machine in the past have been defective. If 15 of the items produced during a day are selected at random, calculate the probability that:
eatleast
Algebra.Com
Question 728408: 7% of the items produced on a machine in the past have been defective. If 15 of the items produced during a day are selected at random, calculate the probability that:
eatleast two of the items is deffective
This is my attempt: 2/15 (7%) + 3/15 (7%) = 0.093 + 0.014 = 0.107
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
7% of the items produced on a machine in the past have been defective. If 15 of the items produced during a day are selected at random, calculate the probability that: at least two of the items are defective
-----------
P(2<= x <=15) = 1 - P(0<= x <=1) = 1 - [(0.93)^15 + (15(0.07)(0.93)^14]
---
= 1 - [0.7168]
----------
= 0.2832
-----------------
Cheers,
Stan H.
RELATED QUESTIONS
7.Ten percent of the items produced by a machine are defective. Out of 15 items chosen at (answered by stanbon)
It is known that 10% of the items produced by a certain machine are defective. Find the... (answered by mathmate)
Seven percent of the items produced at a factory are defective. The quality control team... (answered by robertb)
Can someone help me with this problem:
In a certain production process, 25% of the... (answered by rothauserc,ewatrrr)
In a manufacturing plant, three machines, A, B, and C, produce 40%, 33%, and 27%,... (answered by ewatrrr)
When a particular machine is functioning properly, 80% of the items
produced are... (answered by Boreal)
Suppose that it is known that 5% of the items produced by a particular machine are... (answered by stanbon)
Three machines X, Y, Z are produced respectively 50%, 30% and 20% of the total number of... (answered by Theo)
For a certain manufacturer, only 4/5 of the items produced are not defective. If 2,000... (answered by josmiceli)