SOLUTION: Find the standard score (z) such that the area above the mean and below z under the normal curve is 0.4882.

Question 710190: Find the standard score (z) such that the area above the mean and below z under the normal curve is 0.4882.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the standard score (z) such that the area above the mean and below z under the normal curve is 0.4882.
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Draw the picture.
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The right tail must be 0.5000-0.4882 = 0.0118
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Find the z-value with a left tail of 0.0118
invNorm(0.0118) = -2.2636
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By symmetry your answer is +2.2636
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Cheers,
Stan H.
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