SOLUTION: I have seven books. How many different orders can I read the books in?

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Question 702762: I have seven books. How many different orders can I read the books in?
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
I have seven books. How many different orders can I read the books in?
-----------------
The 1st choice is 1 of 7.
Then 1 of 6, etc
--> 7*6*5*4*3*2*1
= 7!
= 5040 ways
Answer by Edwin McCravy(20063)   (Show Source): You can put this solution on YOUR website!
You can choose the book to read 1st in 7 ways.

Having chosen the first book to read, there are 6 books 
left to choose to read 2nd.  So there are 7×6 ways 
to choose to read the first 2 books.

Having chosen the first 2 books to read, there are 5 books 
left to choose to read 3rd.  So there are 7×6×5 ways 
to choose to read the first 3 books.

Having chosen the first 3 books to read, there are 4 books 
left to choose to read 4th.  So there are 7×6×5×4 ways 
to choose to read the first 4 books. 

Having chosen the first 4 books to read, there are 3 books 
left to choose to read 5th.  So there are 7×6×5×4×3 ways 
to choose to read the first 5 books.

Having chosen the first 5 books to read, there are 2 books 
left to choose to read 6th.  So there are 7×6×5×4×3×2 ways 
to choose to read the first 6 books.

Having chosen the first 6 books to read, there is only 1 book 
left to read 7th.  So there are 7×6×5×4×3×2×1 ways 
to choose to read all 7 books. 

Answer: 7×6×5×4×3×2×1 = 7! = 5040 different orders. 

Edwin
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