SOLUTION: Three identical slips of paper with the numbers 1, 2, and 3 (one number on each slip) are placed in a box.One slip is randomly selected, and then,without replacement, a second

Question 694977: Three identical slips of paper with the numbers 1, 2,
and 3 (one number on each slip) are placed in a box.One
slip is randomly selected, and then,without
replacement, a second slip is selected. Find the
probability that the sum of the two numbers is even.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Three identical slips of paper with the numbers 1, 2,
and 3 (one number on each slip) are placed in a box.One
slip is randomly selected, and then,without
replacement, a second slip is selected. Find the
probability that the sum of the two numbers is even.
-----
Total number of results: 3*2 = 6
------
Even results: 1+3 = 4 ; 3+1 = 4 = 2 ways
----
Ans: P(even sum) = 2/6 = 1/3
================
Cheers,
Stan H.
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