SOLUTION: A box of contains three oranges and 5 cherry candies. If 4 candies are chosen at random what is the probability that no more than one will be orange?

Question 681795: A box of contains three oranges and 5 cherry candies. If 4 candies are chosen at random what is the probability that no more than one will be orange?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A box of contains three oranges and 5 cherry candies. If 4 candies are chosen at random what is the probability that no more than one will be orange?
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# of ways to succeed: 3C0*5C4 + 3C1*5C3 = 1*5+3*10 = 35
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# of possible outcomes: 8C4 = (8*7*6*5)/(1*2*3*4) = 70
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P(0<= x <=1 orange) = 35/70 = 1/2
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Cheers,
Stan H.

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