SOLUTION: A box contains 23 yellow, 30 green and 31 red jelly beans. If 14 jelly beans are selected at random, what is the probability that: a) 12 are yellow? b) 12 are yellow and 1 a

Question 669084: A box contains 23 yellow, 30 green and 31 red jelly beans.
If 14 jelly beans are selected at random, what is the probability that:
a) 12 are yellow?
b) 12 are yellow and 1 are green?
c) At least one is yellow?
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!
A box contains 23 yellow, 30 green and 31 red jelly beans.
If 14 jelly beans are selected at random, what is the probability that:
a) 12 are yellow?

I assume you mean EXACTLY 12 yellow and EXACTLY 2 non-yellow ones

 = .0000007796187072

b) 12 are yellow and 1 are green?

I assume you mean EXACTLY 12 yellow, EXACTLY 1 green and 
EXACTLY 1 red

 = .0000003352458754

c) At least one is yellow?

We calculate the probability of the complement event, that none are
yellow, and subtract from 1:

1 -  =.9929065388

Edwin

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